Finish section on category of sets
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Andrea Vezzosi <vezzosi@chalmers.se> Tue, Apr 24, 2018 at 2:02 PM
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To: Frederik Hanghøj Iversen <fhi.1990@gmail.com>
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Cc: Thierry Coquand <coquand@chalmers.se>
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On Tue, Apr 24, 2018 at 12:57 PM, Frederik Hanghøj Iversen
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<fhi.1990@gmail.com> wrote:
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> I've written the first few sections about my implementation. I was wondering
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> if you could have a quick look at it. You don't need to read it
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> word-for-word but I would like some indication from you if this is the sort
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> of thing you would like to see in the final report.
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Yes! I would say this very much fits the bill of what the main part of
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the report should be, then you could have a discussion section where
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you might put some analysis of the pros and cons of cubical, design
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choices you made, and your experience overall.
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I wonder if there should be some short introduction to Cubical Type
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Theory before this chapter, so you can introduce the Path type by
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itself and show some simple proof with it. e.g. how to get function
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extensionality.
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You mention a few "combinators" like propPi and lemPropF, you might
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want to call them just lemmas, so it's clearer that these can be
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proven in --cubical.
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>
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> I refer you specifically to "Chapter 2 - Implementation" on p. 6.
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>
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> In this chapter I plan to additionally include some text about the proof we
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> did that products are mere propositions and the proof about the two
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> equivalent notions of a monad.
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I've read the chapter up until 2.3 and skimmed the rest for now, but I
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accumulated some editing suggestions I copy here.
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Remember to look for things like these when you proof-read the rest :)
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You should be careful to properly introduce things before you use
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them, like IsPreCategory (I'd prefer if it took the raw category as
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argument btw) and its fields isIdentity, isAssociative, .. come up a
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bit out of the blue from the end of page 8.
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Maybe the easiest is to show the definition of IsPreCategory.
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Maybe give a type for propIsIdentity and mention the other prop* are similar.
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Also the notation "isIdentity_a" to apply projections is a bit unusual
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so it needs to be introduced as well.
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To be fair it would be simpler to stick to function application
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(though I see that it would introduce more parentheses),
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"The situation is a bit more complicated when we have a dependent
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type" could be more clear by being more specific:
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"The situation is a bit more complicated when the type of a field
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depends on a previous field"
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Here too it might be more concrete if you also give the code for IsCategory.
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In Path ( λ i → Univalent_{p i} ) isPreCategory_a isPreCategory_b
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I suggest parentheses around (p i), but also you should be consistent
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on whether you want to call the proof "p" or "p_{isPreCategory}",
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finally i'm guessing the two fields should be "isUnivalent" rather
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than "isPreCategory".
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You can cite the book on the specific definition of isEquiv,
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"contractible fibers" in section 4.4, the grad lemma is also from
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somewhere but I don't remember off-hand.
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You have not defined what you mean by _\~=_ and isomorphism.
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Cheers,
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Andrea
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[Quoted text hidden]
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@ -189,7 +189,7 @@ $$
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and one heterogeneous:
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%
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$$
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Path\ (\lambda i \to Univalent_{p\ i})\ \isPreCategory_a\ \isPreCategory_b
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\Path\ (\lambda\; i \mto Univalent_{p\ i})\ \isPreCategory_a\ \isPreCategory_b
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$$
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%
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Which depends on the choice of $p_{\isPreCategory}$. The first of these we can
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@ -203,7 +203,7 @@ path between some two elements in $A$; $p : a_0 \equiv a_1$ then we can built a
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heterogeneous path between any two $b$'s at the endpoints:
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%
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$$
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Path\ (\lambda i \to B\ (p\ i))\ b0\ b1
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\Path\ (\lambda\; i \mto B\ (p\ i))\ b0\ b1
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$$
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%
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where $b_0 \tp B a_0$ and $b_1 \tp B\ a_1$. This is quite a mouthful, but the
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@ -216,7 +216,7 @@ applying using congruence of paths: $\congruence\ \mathit{isIdentity}\
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p_{\isPreCategory}$
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When we have a proper category we can make precise the notion of ``identifying
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isomorphic types'' (TODO cite awodey here). That is, we can construct the
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isomorphic types'' \TODO{cite awodey here}. That is, we can construct the
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function:
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%
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$$
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@ -227,11 +227,11 @@ One application of this, and a perhaps somewhat surprising result, is that
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terminal objects are propositional. Intuitively; they do not have any
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interesting structure. The proof of this follows from the usual observation that
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any two terminal objects are isomorphic. The proof is omitted here, but the
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curious reader can check the implementation for the details. (TODO: The proof is
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a bit fun, should I include it?)
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curious reader can check the implementation for the details. \TODO{The proof is
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a bit fun, should I include it?}
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\section{Equivalences}
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\label{equiv}
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\label{sec:equiv}
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The usual notion of a function $f : A \to B$ having an inverses is:
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%
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$$
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@ -253,7 +253,7 @@ what an equivalence $\isEquiv : (A \to B) \to \MCU$ must supply:
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%
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Having such an interface gives us both 1) a way to think rather abstractly about
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how to work with equivalences and 2) to use ad-hoc definitions of equivalences.
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The specific instantiation of $\isEquiv$ as defined in \cite{cubical} is:
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The specific instantiation of $\isEquiv$ as defined in \cite{cubical-agda} is:
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%
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$$
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isEquiv\ f \defeq \prod_{b : B} \isContr\ (\fiber\ f\ b)
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@ -269,7 +269,7 @@ once we have shown that this definition actually works as an equivalence.
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The first function from the list of requirements we will call
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$\mathit{fromIsomorphism}$, this is known as $\mathit{gradLemma}$ in
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\cite{cubical} the second one we will refer to as $\mathit{toIsmorphism}$. It's
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\cite{cubical-agda} the second one we will refer to as $\mathit{toIsmorphism}$. It's
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implementation can be found in the sources. Likewise the proof that this
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equivalence is propositional can be found in my implementation.
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@ -353,7 +353,7 @@ $$
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\isoToId \tp A \approxeq B \to A \equiv B
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$$
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%
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The next few theorems are variations on theorem 9.1.9 from \cite{HoTT-book}. Let
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The next few theorems are variations on theorem 9.1.9 from \cite{hott-2013}. Let
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an isomorphism $A \approxeq B$ in some category $\bC$ be given. Name the
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isomorphism $\iota \tp A \to B$ and its inverse $\widetilde{\iota} \tp B \to A$.
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Since $\bC$ is a category (and therefore univalent) the isomorphism induces a
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@ -425,7 +425,7 @@ univalence in a very simple category where the structure of the category is
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rather simple.
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Let $\bC$ be some category, we then define the opposite category
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$\bC^{\matit{Op}}$. It has the same objects, but the type of arrows are flipped,
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$\bC^{\mathit{Op}}$. It has the same objects, but the type of arrows are flipped,
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that is to say an arrow from $A$ to $B$ in the opposite category corresponds to
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an arrow from $B$ to $A$ in the underlying category. The identity arrow is the
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same as the one in the underlying category (they have the same type). Function
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@ -442,7 +442,7 @@ Since $\rrr$ is reverse function composition this is just the symmetric version
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of associativity.
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%
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$$
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\matit{identity} \rrr f \equiv f \x f \rrr identity \equiv f
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\mathit{identity} \rrr f \equiv f \x f \rrr identity \equiv f
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$$
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%
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This is just the swapped version of identity.
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@ -452,7 +452,7 @@ arguments. Or in other words since $\Hom_{A\ B}$ is a set for all $A\ B \tp
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\Object$ then so is $\Hom_{B\ A}$.
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Now, to show that this category is univalent is not as straight-forward. Lucliy
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section \ref{equiv} gave us some tools to work with equivalences. We saw that we
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section \ref{sec:equiv} gave us some tools to work with equivalences. We saw that we
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can prove this category univalent by giving an inverse to
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$\idToIso_{\mathit{Op}} \tp (A \equiv B) \to (A \approxeq_{\mathit{Op}} B)$.
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From the original category we have that $\idToIso \tp (A \equiv B) \to (A \cong
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@ -500,7 +500,7 @@ This finished the proof that the opposite category is in fact a category. Now,
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to prove that that opposite-of is an involution we must show:
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%
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$$
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\prod_{\bC \tp \mathit{Category}} \left(\bC^{\matit{Op}}\right)^{\matit{Op}} \equiv \bC
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\prod_{\bC \tp \mathit{Category}} \left(\bC^{\mathit{Op}}\right)^{\mathit{Op}} \equiv \bC
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$$
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%
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As we've seen the laws in $\left(\bC^{\mathit{Op}}\right)^{\mathit{Op}}$ get
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@ -543,20 +543,23 @@ $$
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%
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Which, as we saw in section \ref{univalence}, is sufficient to show that the
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category is univalent. The way that I have shown this is with a three-step
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process. For objects $(A, s_A)\; (B, s_B) \tp \Set$ I show that.
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process. For objects $(A, s_A)\; (B, s_B) \tp \Set$ I show the following chain
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of equivalences:
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%
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\begin{align*}
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((A, s_A) \equiv (B, s_B)) & \simeq (A \equiv B) \\
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(A \equiv B) & \simeq (\fst A \simeq \fst B) \\
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(A \simeq B) & \simeq ((A, s_A) \approxeq (B, s_B))
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((A, s_A) \equiv (B, s_B))
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& \simeq (A \equiv B) && \ref{eq:equivPropSig} \\
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& \simeq (A \simeq B) && \text{Univalence} \\
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& \simeq ((A, s_A) \approxeq (B, s_B)) && \text{\ref{eq:equivSig} and \ref{eq:equivIso}}
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\end{align*}
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And since $\simeq$ is an equivalence relation we can chain these equivalences
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together. Step one will be proven with the following lemma:
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%
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$$
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\begin{align}
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\label{eq:equivPropSig}
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\left(\prod_{a \tp A} \isProp (P\ a)\right) \to \prod_{x\;y \tp \sum_{a \tp A} P\ a} (x \equiv y) \simeq (\fst\ x \equiv \fst\ y)
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$$
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\end{align}
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%
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The lemma states that for pairs whose second component are mere propositions
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equiality is equivalent to equality of the first components. In this case the
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@ -564,21 +567,105 @@ type-family $P$ is $\isSet$ which itself is a proposition for any type $A \tp
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\Type$. Step two is univalence. Step three will be proven with the following
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lemma:
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%
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$$
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\begin{align}
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\label{eq:equivSig}
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\prod_{a \tp A} \left( P\ a \simeq Q\ a \right) \to \sum_{a \tp A} P\ a \simeq \sum_{a \tp A} Q\ a
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$$
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\end{align}
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%
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Which says that if two type-families are equivalent at all points, then pairs
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with identitical first components and these families as second components will
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also be equivalent. For our purposes $P \defeq \isEquiv\ A\ B$ and $Q \defeq
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\mathit{Isomorphism}$. So we must finally prove:
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%
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$$
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\begin{align}
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\label{eq:equivIso}
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\prod_{f \tp A \to B} \left( \isEquiv\ A\ B\ f \simeq \mathit{Isomorphism}\ f \right)
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$$
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\end{align}
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First, lets proove \ref{eq:equivPropSig}: Let $propP \tp \prod_{a \tp A} \isProp (P\ a)$ and $x\;y \tp \sum_{a \tp A} P\ a$ be given. Because
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of $\mathit{fromIsomorphism}$ it suffices to give an isomorphism between
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$x \equiv y$ and $\fst\ x \equiv \fst\ y$:
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%
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\begin{align*}
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f & \defeq \congruence\ \fst \tp x \equiv y \to \fst\ x \equiv \fst\ y \\
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g & \defeq \mathit{lemSig}\ \mathit{propP}\ x\ y \tp \fst\ x \equiv \fst\ y \to x \equiv y
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\end{align*}
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%
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\TODO{Is it confusing that I use point-free style here?}
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Here $\mathit{lemSig}$ is a lemma that says that if the second component of a
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pair is a proposition, it suffices to give a path between it's first components
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to construct an equality of the two pairs:
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%
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\begin{align*}
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\mathit{lemSig} \tp \left( \prod_{x \tp A} \isProp\ (B\ x) \right) \to
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\prod_{u\; v \tp \sum_{a \tp A} B\ a}
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\left( \fst\ u \equiv \fst\ v \right) \to u \equiv v
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\end{align*}
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%
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The proof that these are indeed inverses has been omitted. \TODO{Do I really
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want to ommit it?}\QED
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\subsection{Categories}
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Now to prove \ref{eq:equivSig}: Let $e \tp \prod_{a \tp A} \left( P\ a \simeq
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Q\ a \right)$ be given. To prove the equivalence, it suffices to give an
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isomorphism between $\sum_{a \tp A} P\ a$ and $\sum_{a \tp A} Q\ a$, but since
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they have identical first components it suffices to give an isomorphism between
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$P\ a$ and $Q\ a$ for all $a \tp A$. This is exactly what we can get from
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the equivalence $e$.\QED
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Lastly we prove \ref{eq:equivIso}. Let $f \tp A \to B$ be given. For the maps we
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choose:
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%
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\begin{align*}
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\mathit{toIso}
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& \tp \isEquiv\ f \to \mathit{Isomorphism}\ f \\
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\mathit{fromIso}
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& \tp \mathit{Isomorphism}\ f \to \isEquiv\ f
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\end{align*}
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%
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As mentioned in section \ref{sec:equiv}. These maps are not in general inverses
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of each other. In stead, we will use the fact that $A$ and $B$ are sets. The first thing we must prove is:
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%
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\begin{align*}
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\mathit{fromIso} \comp \mathit{toIso} \equiv \identity_{\isEquiv\ f}
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\end{align*}
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%
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For this we can use the fact that being-an-equivalence is a mere proposition.
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For the other direction:
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%
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\begin{align*}
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\mathit{toIso} \comp \mathit{fromIso} \equiv \identity_{\mathit{Isomorphism}\ f}
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\end{align*}
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%
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We will show that $\mathit{Isomorphism}\ f$ is also a mere proposition. To this
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end, let $X\;Y \tp \mathit{Isomorphism}\ f$ be given. Name the maps $x\;y \tp B
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\to A$ respectively. Now, the proof that $X$ and $Y$ are the same is a pair of
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paths: $p \tp x \equiv y$ and $\Path\ (\lambda\; i \mto
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\mathit{AreInverses}\ f\ (p\ i))\ \mathcal{X}\ \mathcal{Y}$ where $\mathcal{X}$
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and $\mathcal{Y}$ denotes the witnesses that $x$ (respectively $y$) is an
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inverse to $f$. $p$ is inhabited by:
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%
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\begin{align*}
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x
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& \equiv x \comp \identity \\
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& \equiv x \comp (f \comp y)
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&& \text{$y$ is an inverse to $f$} \\
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& \equiv (x \comp f) \comp y \\
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& \equiv \identity \comp y
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&& \text{$x$ is an inverse to $f$} \\
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& \equiv y
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\end{align*}
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%
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For the other (dependent) path we can prove that being-an-inverse-of is a
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proposition and then use $\lemPropF$. So we prove the generalization:
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%
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\begin{align*}
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\prod_{g : B \to A} \isProp\ (\mathit{AreInverses}\ f\ g)
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\end{align*}
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%
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But $\mathit{AreInverses}\ f\ g$ is a pair of equations on arrows, so we use
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$\propSig$ and the fact that both $A$ and $B$ are sets to close this proof.
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\subsection{Category of categories}
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Note that this category does in fact not exist. In stead I provide the
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definition of the ``raw'' category as well as some of the laws.
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@ -589,8 +676,40 @@ These lemmas can be used to provide the actual exponential object in a context
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where we have a witness to this being a category. This is useful if this library
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is later extended to talk about higher categories.
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\section{Product}
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In the following I'll demonstrate a technique for using categories to prove
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properties. The goal in this section is to show that products are propositions:
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%
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$$
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\prod_{\bC \tp \Category} \prod_{A\;B \tp \Object} \isProp\ (\mathit{Product}\ \bC\ A\ B)
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$$
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%
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Where $\mathit{Product}\ \bC\ A\ B$ denotes the type of products of objects $A$
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and $B$ in the category $\bC$. I do this by constructing a category whose
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terminal objects are equivalent to products in $\bC$, and since terminal objects
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are propositional in a proper category and equivalences preservehomotopy level,
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then we know that products also are propositions. But before we get to that,
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let's recall the definition of products.
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Given a category $\bC$ and two objects $A$ and $B$ in $bC$ we define the product
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of $A$ and $B$ to be an object $A \x B$ in $\bC$ and two arrows $\pi_1 \tp A \x
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B \to A$ and $\pi_2 \tp A \x B \to B$ called the projections of the product. The projections must satisfy the following property:
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For all $X \tp Object$, $f \tp \Arrow\ X\ A$ and $g \tp \Arrow\ X\ B$ we have
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that there exists a unique arrow $\pi \tp \Arrow\ X\ (A \x B)$ satisfying
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%
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\begin{align}
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\label{eq:umpProduct}
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%% \prod_{X \tp Object} \prod_{f \tp \Arrow\ X\ A} \prod_{g \tp \Arrow\ X\ B}\\
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%% \uexists_{f \x g \tp \Arrow\ X\ (A \x B)}
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\pi_1 \lll \pi \equiv f \x \pi_2 \lll \pi \equiv g
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%% ump : ∀ {X : Object} (f : ℂ [ X , A ]) (g : ℂ [ X , B ])
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%% → ∃![ f×g ] (ℂ [ fst ∘ f×g ] ≡ f P.× ℂ [ snd ∘ f×g ] ≡ g)
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\end{align*}
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$
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$\pi$ is called the product (arrow) of $f$ and $g$.
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\section{Monads}
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%% \subsubsection{Functors}
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|
@ -73,12 +73,13 @@ the (left) identity law of the underlying category to proove $\idFun \comp g
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%
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\subsection{Equality of isomorphic types}
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%
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Let $\top$ denote the unit type -- a type with a single constructor. In the
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propositions-as-types interpretation of type theory $\top$ is the proposition
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that is always true. The type $A \x \top$ and $A$ has an element for each $a :
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A$. So in a sense they are the same. The second element of the pair does not add
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any ``interesting information''. It can be useful to identify such types. In
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fact, it is quite commonplace in mathematics. Say we look at a set $\{x \mid
|
||||
Let $\top$ denote the unit type -- a type with a single constructor. In
|
||||
the propositions-as-types interpretation of type theory $\top$ is the
|
||||
proposition that is always true. The type $A \x \top$ and $A$ has an element for
|
||||
each $a : A$. So in a sense they are the same. The second element of the pair
|
||||
does not add any ``interesting information''. It can be useful to identify such
|
||||
types. In fact, it is quite commonplace in mathematics. Say we look at a set
|
||||
$\{x \mid
|
||||
\phi\ x \land \psi\ x\}$ and somehow conclude that $\psi\ x \equiv \top$ for all
|
||||
$x$. A mathematician would immediately conclude $\{x \mid \phi\ x \land
|
||||
\psi\ x\} \equiv \{x \mid \phi\ x\}$ without thinking twice. Unfortunately such
|
||||
|
@ -92,8 +93,9 @@ types. The principle of univalence says that:
|
|||
%
|
||||
$$\mathit{univalence} \tp (A \simeq B) \simeq (A \equiv B)$$
|
||||
%
|
||||
In particular this allows us to construct an equality from an equivalence $\mathit{ua} \tp
|
||||
(A \simeq B) \to (A \equiv B)$ and vice-versa.
|
||||
In particular this allows us to construct an equality from an equivalence
|
||||
($\mathit{ua} \tp (A \simeq B) \to (A \equiv B)$) and vice-versa.
|
||||
|
||||
\section{Formalizing Category Theory}
|
||||
%
|
||||
The above examples serve to illustrate the limitation of Agda. One case where
|
||||
|
@ -115,20 +117,21 @@ Inspiration:
|
|||
\end{verbatim}
|
||||
The idea of formalizing Category Theory in proof assistants is not new. There
|
||||
are a multitude of these available online. Just as first reference see this
|
||||
question on Math Overflow: \cite{mo-formalizations}. Notably these two implementations of category theory in Agda:
|
||||
question on Math Overflow: \cite{mo-formalizations}. Notably these
|
||||
implementations of category theory in Agda:
|
||||
\begin{itemize}
|
||||
\item
|
||||
\url{https://github.com/copumpkin/categories} - setoid interpretation
|
||||
\url{https://github.com/copumpkin/categories} -- setoid interpretation
|
||||
\item
|
||||
\url{https://github.com/pcapriotti/agda-categories} - homotopic setting with postulates
|
||||
\url{https://github.com/pcapriotti/agda-categories} -- homotopic setting with postulates
|
||||
\item
|
||||
\url{https://github.com/pcapriotti/agda-categories} - homotopic setting in coq
|
||||
\url{https://github.com/pcapriotti/agda-categories} -- homotopic setting in coq
|
||||
\item
|
||||
\url{https://github.com/mortberg/cubicaltt} - homotopic setting in \texttt{cubicaltt}
|
||||
\url{https://github.com/mortberg/cubicaltt} -- homotopic setting in \texttt{cubicaltt}
|
||||
\end{itemize}
|
||||
The contribution of this
|
||||
thesis is to explore how working in a cubical setting will make it possible to
|
||||
prove more things and to reuse proofs.
|
||||
|
||||
The contribution of this thesis is to explore how working in a cubical setting
|
||||
will make it possible to prove more things and to reuse proofs.
|
||||
|
||||
There are alternative approaches to working in a cubical setting where one can
|
||||
still have univalence and functional extensionality. One option is to postulate
|
||||
|
|
|
@ -59,3 +59,9 @@
|
|||
\newcommand\rrr{\ggg}
|
||||
\newcommand\fst{\mathit{fst}}
|
||||
\newcommand\snd{\mathit{snd}}
|
||||
\newcommand\Path{\mathit{Path}}
|
||||
\newcommand\Category{\mathit{Category}}
|
||||
\newcommand\TODO[1]{TODO: \emph{#1}}
|
||||
\newcommand*{\QED}{\hfill\ensuremath{\square}}%
|
||||
\newcommand\uexists{\exists!}
|
||||
\newcommand\Arrow{\mathit{Arrow}}
|
||||
|
|
|
@ -26,8 +26,8 @@
|
|||
\bibliographystyle{plainnat}
|
||||
\nocite{cubical-demo}
|
||||
\nocite{coquand-2013}
|
||||
%% \bibliography{refs}
|
||||
%% \begin{appendices}
|
||||
\bibliography{refs}
|
||||
\begin{appendices}
|
||||
%% \input{planning.tex}
|
||||
%% \input{halftime.tex}
|
||||
\end{appendices}
|
||||
|
|
|
@ -10,7 +10,7 @@ open import Cubical.GradLemma hiding (isoToPath)
|
|||
open import Cat.Prelude using
|
||||
( lemPropF ; setPi ; lemSig ; propSet
|
||||
; Preorder ; equalityIsEquivalence ; propSig ; id-coe
|
||||
; Setoid )
|
||||
; Setoid ; _$_ ; propPi )
|
||||
|
||||
import Cubical.Univalence as U
|
||||
|
||||
|
@ -133,7 +133,7 @@ module _ {ℓa ℓb ℓ : Level} (A : Set ℓa) (B : Set ℓb) where
|
|||
-- | The other inverse law does not hold in general, it does hold, however,
|
||||
-- | if `A` and `B` are sets.
|
||||
module _ (sA : isSet A) (sB : isSet B) where
|
||||
module _ {f : A → B} (iso : Isomorphism f) where
|
||||
module _ {f : A → B} where
|
||||
module _ (iso-x iso-y : Isomorphism f) where
|
||||
open Σ iso-x renaming (fst to x ; snd to inv-x)
|
||||
open Σ iso-y renaming (fst to y ; snd to inv-y)
|
||||
|
@ -146,22 +146,18 @@ module _ {ℓa ℓb ℓ : Level} (A : Set ℓa) (B : Set ℓb) where
|
|||
y ∎
|
||||
|
||||
propInv : ∀ g → isProp (AreInverses f g)
|
||||
propInv g t u i = a i , b i
|
||||
propInv g t u = λ i → a i , b i
|
||||
where
|
||||
a : (fst t) ≡ (fst u)
|
||||
a i = h
|
||||
a i = funExt hh
|
||||
where
|
||||
hh : ∀ a → (g ∘ f) a ≡ a
|
||||
hh a = sA ((g ∘ f) a) a (λ i → (fst t) i a) (λ i → (fst u) i a) i
|
||||
h : g ∘ f ≡ idFun A
|
||||
h i a = hh a i
|
||||
b : (snd t) ≡ (snd u)
|
||||
b i = h
|
||||
b i = funExt hh
|
||||
where
|
||||
hh : ∀ b → (f ∘ g) b ≡ b
|
||||
hh b = sB _ _ (λ i → snd t i b) (λ i → snd u i b) i
|
||||
h : f ∘ g ≡ idFun B
|
||||
h i b = hh b i
|
||||
|
||||
inx≡iny : (λ i → AreInverses f (fx≡fy i)) [ inv-x ≡ inv-y ]
|
||||
inx≡iny = lemPropF propInv fx≡fy
|
||||
|
@ -169,11 +165,12 @@ module _ {ℓa ℓb ℓ : Level} (A : Set ℓa) (B : Set ℓb) where
|
|||
propIso : iso-x ≡ iso-y
|
||||
propIso i = fx≡fy i , inx≡iny i
|
||||
|
||||
inverse-to-from-iso : (toIso {f} ∘ fromIso {f}) iso ≡ iso
|
||||
inverse-to-from-iso = begin
|
||||
(toIso ∘ fromIso) iso ≡⟨⟩
|
||||
toIso (fromIso iso) ≡⟨ propIso _ _ ⟩
|
||||
iso ∎
|
||||
module _ (iso : Isomorphism f) where
|
||||
inverse-to-from-iso : (toIso {f} ∘ fromIso {f}) iso ≡ iso
|
||||
inverse-to-from-iso = begin
|
||||
(toIso ∘ fromIso) iso ≡⟨⟩
|
||||
toIso (fromIso iso) ≡⟨ propIso _ _ ⟩
|
||||
iso ∎
|
||||
|
||||
fromIsomorphism : A ≅ B → A ~ B
|
||||
fromIsomorphism (f , iso) = f , fromIso iso
|
||||
|
@ -419,7 +416,7 @@ module _ {ℓa ℓb : Level} {A : Set ℓa} {P : A → Set ℓb} where
|
|||
equivPropSig pA p q = fromIsomorphism _ _ iso
|
||||
where
|
||||
f : ∀ {p q} → p ≡ q → fst p ≡ fst q
|
||||
f e i = fst (e i)
|
||||
f = cong fst
|
||||
g : ∀ {p q} → fst p ≡ fst q → p ≡ q
|
||||
g {p} {q} = lemSig pA p q
|
||||
ve-re : (e : p ≡ q) → (g ∘ f) e ≡ e
|
||||
|
@ -507,31 +504,26 @@ module _ {ℓa ℓb : Level} {A : Set ℓa} {P : A → Set ℓb} where
|
|||
→ ((a : A) → P a ≃ Q a) → Σ A P ≃ Σ A Q
|
||||
equivSig {Q = Q} eA = res
|
||||
where
|
||||
P≅Q : ∀ {a} → P a ≅ Q a
|
||||
P≅Q {a} = toIsomorphism _ _ (eA a)
|
||||
f : Σ A P → Σ A Q
|
||||
f (a , pA) = a , fst (eA a) pA
|
||||
f (a , pA) = a , fst P≅Q pA
|
||||
g : Σ A Q → Σ A P
|
||||
g (a , qA) = a , g' qA
|
||||
where
|
||||
k : Isomorphism _
|
||||
k = toIso _ _ (snd (eA a))
|
||||
open Σ k renaming (fst to g')
|
||||
g (a , qA) = a , fst (snd P≅Q) qA
|
||||
ve-re : (x : Σ A P) → (g ∘ f) x ≡ x
|
||||
ve-re x i = fst x , eq i
|
||||
ve-re (a , pA) i = a , eq i
|
||||
where
|
||||
eq : snd ((g ∘ f) x) ≡ snd x
|
||||
eq : snd ((g ∘ f) (a , pA)) ≡ pA
|
||||
eq = begin
|
||||
snd ((g ∘ f) x) ≡⟨⟩
|
||||
snd ((g ∘ f) (a , pA)) ≡⟨⟩
|
||||
snd (g (f (a , pA))) ≡⟨⟩
|
||||
g' (fst (eA a) pA) ≡⟨ lem ⟩
|
||||
pA ∎
|
||||
where
|
||||
open Σ x renaming (fst to a ; snd to pA)
|
||||
k : Isomorphism _
|
||||
k = toIso _ _ (snd (eA a))
|
||||
open Σ k renaming (fst to g' ; snd to inv)
|
||||
open Σ (snd P≅Q) renaming (fst to g' ; snd to inv)
|
||||
-- anti-funExt
|
||||
lem : (g' ∘ (fst (eA a))) pA ≡ pA
|
||||
lem i = fst inv i pA
|
||||
lem = cong (_$ pA) (fst (snd (snd P≅Q)))
|
||||
re-ve : (x : Σ A Q) → (f ∘ g) x ≡ x
|
||||
re-ve x i = fst x , eq i
|
||||
where
|
||||
|
|
|
@ -62,10 +62,8 @@ module _ (ℓ : Level) where
|
|||
syntax ∃!-syntax (λ x → B) = ∃![ x ] B
|
||||
|
||||
module _ {ℓa ℓb} {A : Set ℓa} {P : A → Set ℓb} (f g : ∃! P) where
|
||||
open Σ (snd f) renaming (snd to u)
|
||||
|
||||
∃-unique : fst f ≡ fst g
|
||||
∃-unique = u (fst (snd g))
|
||||
∃-unique = (snd (snd f)) (fst (snd g))
|
||||
|
||||
module _ {ℓa ℓb : Level} {A : Set ℓa} {B : A → Set ℓb} {a b : Σ A B}
|
||||
(fst≡ : (λ _ → A) [ fst a ≡ fst b ])
|
||||
|
|
Loading…
Reference in a new issue