165 lines
7.6 KiB
TeX
165 lines
7.6 KiB
TeX
\section{Introduction}
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Functional extensionality and univalence is not expressible in
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\nomen{Intensional Martin Löf Type Theory} (ITT). This poses a severe limitation
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on both 1) what is \emph{provable} and 2) the \emph{reusability} of proofs.
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Recent developments have, however, resulted in \nomen{Cubical Type Theory} (CTT)
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which permits a constructive proof of these two important notions.
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Furthermore an extension has been implemented for the proof assistant Agda
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(\cite{agda}, \cite{cubical-agda}) that allows us to work in such a ``cubical
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setting''. This thesis will explore the usefulness of this extension in the
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context of category theory.
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In the following two sections I present two examples that illustrate some
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limitations inherent in ITT and -- by extension -- Agda.
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%
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\subsection{Functional extensionality}
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Consider the functions:
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\begin{multicols}{2}
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$f \defeq (n : \bN) \mapsto (0 + n : \bN)$
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$g \defeq (n : \bN) \mapsto (n + 0 : \bN)$
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\end{multicols}
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$n + 0$ is \nomen{definitionally} equal to $n$ which we write as $n + 0 = n$.
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This is also called \nomen{judgmental} equality. We call it definitional
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equality because the \emph{equality} arises from the \emph{definition} of $+$
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which is:
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%
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\newcommand{\suc}[1]{\mathit{suc}\ #1}
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\begin{align*}
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+ & : \bN \to \bN \\
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n + 0 & \defeq n \\
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n + (\suc{m}) & \defeq \suc{(n + m)}
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\end{align*}
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%
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Note that $0 + n$ is \emph{not} definitionally equal to $n$. $0 + n$ is in
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normal form. I.e.; there is no rule for $+$ whose left-hand-side matches this
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expression. We \emph{do}, however, have that they are \nomen{propositionally}
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equal which we write as $n + 0 \equiv n$. Propositional equality means that
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there is a proof that exhibits this relation. Since equality is a transitive
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relation we have that $n + 0 \equiv 0 + n$.
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Unfortunately we don't have $f \equiv g$.\footnote{Actually showing this is
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outside the scope of this text. Essentially it would involve giving a model
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for our type theory that validates all our axioms but where $f \equiv g$ is
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not true.} There is no way to construct a proof asserting the obvious
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equivalence of $f$ and $g$ -- even though we can prove them equal for all
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points. This is exactly the notion of equality of functions that we are
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interested in; that they are equal for all inputs. We call this
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\nomen{pointwise equality}, where the \emph{points} of a function refers
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to it's arguments.
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In the context of category theory functional extensionality is e.g. needed to
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show that representable functors are indeed functors. The representable functor
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for a category $\bC$ and a fixed object in $A \in \bC$ is defined to be:
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\begin{align*}
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\fmap \defeq X \mapsto \Hom_{\bC}(A, X)
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\end{align*}
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The proof obligation that this satisfies the identity law of functors
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($\fmap\ \idFun \equiv \idFun$) becomes:
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\begin{align*}
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\Hom(A, \idFun_{\bX}) = (g \mapsto \idFun \comp g) \equiv \idFun_{\Sets}
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\end{align*}
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%
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One needs functional extensionality to ``go under'' the function arrow and apply
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the (left) identity law of the underlying category to proove $\idFun \comp g
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\equiv g$ and thus closing the.
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%
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\subsection{Equality of isomorphic types}
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Let $\top$ denote the unit type -- a type with a single constructor. In the
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propositions-as-types interpretation of type theory $\top$ is the proposition
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that is always true. The type $A \x \top$ and $A$ has an element for each $a :
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A$. So in a sense they are the same. The second element of the pair does not add
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any ``interesting information''. It can be useful to identify such types. In
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fact, it is quite commonplace in mathematics. Say we look at a set $\{x \mid
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\phi\ x \land \psi\ x\}$ and somehow conclude that $\psi\ x \equiv \top$ for all
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$x$. A mathematician would immediately conclude $\{x \mid \phi\ x \land
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\psi\ x\} \equiv \{x \mid \phi\ x\}$ without thinking twice. Unfortunately such
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an identification can not be performed in ITT.
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More specifically; what we are interested in is a way of identifying
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\nomen{equivalent} types. I will return to the definition of equivalence later,
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but for now, it is sufficient to think of an equivalence as a one-to-one
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correspondence. We write $A \simeq B$ to assert that $A$ and $B$ are equivalent
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types. The principle of univalence says that:
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$$\mathit{univalence} \tp (A \simeq B) \simeq (A \equiv B)$$
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In particular this allows us to construct an equality from an equivalence $\mathit{ua} \tp
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(A \simeq B) \to (A \equiv B)$ and vice-versa.
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\subsection{Formalizing Category Theory}
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%
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The above examples serve to illustrate the limitation of Agda. One case where
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these limitations are particularly prohibitive is in the study of Category
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Theory. At a glance category theory can be described as ``the mathematical study
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of (abstract) algebras of functions'' (\cite{awodey-2006}). So by that token
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functional extensionality is particularly useful for formulating Category
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Theory. In Category theory it is also common to identify isomorphic structures
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and this is exactly what we get from univalence. In fact we can formulate this
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requirement within our formulation of categories by requiring the
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\emph{categories} themselves to be univalent as we shall see.
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\section{Context}
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%
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\begin{verbatim}
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Inspiration:
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* Awodey - formulation of categories
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* HoTT - sketch of homotopy proofs
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\end{verbatim}
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The idea of formalizing Category Theory in proof assistants is not new. There
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are a multitude of these available online. Just as first reference see this
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question on Math Overflow: \cite{mo-formalizations}. Notably these two implementations of category theory in Agda:
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\begin{itemize}
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\item
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\url{https://github.com/copumpkin/categories} - setoid interpretation
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\item
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\url{https://github.com/pcapriotti/agda-categories} - homotopic setting with postulates
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\item
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\url{https://github.com/pcapriotti/agda-categories} - homotopic setting in coq
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\item
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\url{https://github.com/mortberg/cubicaltt} - homotopic setting in \texttt{cubicaltt}
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\end{itemize}
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The contribution of this
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thesis is to explore how working in a cubical setting will make it possible to
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prove more things and to reuse proofs.
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There are alternative approaches to working in a cubical setting where one can
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still have univalence and functional extensionality. One option is to postulate
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these as axioms. This approach, however, has other shortcomings, e.g.; you lose
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\nomen{canonicity} (\cite{huber-2016}). Canonicity means that any well-typed
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term evaluates to a \emph{canonical} form. For example for a closed term $e :
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\bN$ it will be the case that $e$ reduces to $n$ applications of $\mathit{suc}$
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to $0$ for some $n$; $e = \mathit{suc}^n\ 0$. Without canonicity terms in the
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language can get ``stuck'' -- meaning that they do not reduce to a canonical
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form.
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Another approach is to use the \emph{setoid interpretation} of type theory
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(\cite{hofmann-1995,huber-2016}). With this approach one works with
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\nomen{extensionals sets} $(X, \sim)$, that is a type $X \tp \MCU$ and an
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equivalence relation $\sim$.
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Types should additionally `carry around' an equivalence relation that serve as
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propositional equality. This approach has other drawbacks; it does not satisfy
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all judgemental equalites of type theory, is cumbersome to work with in practice
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(\cite[p. 4]{huber-2016}) and makes equational proofs less reusable since
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equational proofs $a \sim_{X} b$ are inherently `local' to the extensional set
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$(X , \sim)$.
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%
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\section{The equality type}
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The usual definition of equality in Agda is an inductive data-type with a single
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constructor:
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%
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%% \VerbatimInput{../libs/main.tex}
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% \def\verbatim@font{xits}
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\begin{verbatim}
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data _≡_ {a} {A : Set a} (x : A) : A → Set a where
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instance refl : x ≡ x
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\end{verbatim}
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